A force `2hati+hatj-hatk` newton acts on a body which is initially at rest.If the velocity of the body at the end of `20seconds` is `4hati+2hatj+2hatk ms^(-1)`, the mass of the body

A force 3hati+2hatj+hatk newtons acts on aa body which is initially at rest. At the end of 10 seconds the velocity of the body is 2hati+2hatj-2hatk m//s . What is the mass of the body?

A force of (3 hati + 4 hatj) Newton acts on a body and it by (3 hati + 4 hatj)m . The work done by the force is

A force 2hati+3hatj+4hatk N acts on a body for 4 sec, produces a displacement of (3hati+4hatj+5hatk) m. the power used is

A force 2hati+3hatj+4hatk N acts on a body for 4 sec, produces a displacement of (3hati+4hatj+5hatk) m. the power used is

A force F=(2hati+3hatj-hatk)N is acting on a body at a position r=(6hati-3hatj-2hatk) . Calculate the torque about the origin

A force (4hati+hatj-2hatk) N acting on a body maintains its velocity at (2hati+2hatj+3hatk) m s^(-1) . The power exerted is