An aqueous solution of a non-volatile solute boils at `100.17^(@)C`. At what temperature will the solution freeze? (Given: `K_(b) = 0.512` and `K_(f) = 1.86`)

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .

A 5 per cent aqueous solution by mass of a non-volatile solute boils at 100.15^(@)C . Calculate the molar mass of the solute. K_(b)=0.52 K kg "mol"^(-1) .

An aqueous dilute solution containing non- volatile solute boils at 100.052 ""^(@) C what is the molality of solution ? K_(b) = 0.52 kg mol ^(-1) K, Boiling temperature of water =100^(@) C )

An aqueous dilute solution containing non- volatile solute boils at 100.052 ""^(@) C . What is the molality of solution ? K_(b) = 0.52 kg mol ^(-1) K, Boiling temperature of water =100^(@) C .

An aqueous solution of a non-volatile solute freezes at 272.4 K, while pure water freezes at 273.0 K. Determine the following: (Given K_(f)= 1.86 "K kg mol"^(-1), K_(b) = 0.512 "K kg mol"^(-1) and vapour pressure of water at 298 K = 23.756 mm of Hg) (1) The molality of solution (2) Boiling point of solution (3) The lowering of vapour pressure of water at 298 K

Difference in boiling point and freezing point of 10kg aqeous solution of urea is 100.2372^(@)C ,then what quantity of urea dissolved in the solution ? ( K_(b) = 0.512^(@)C and K_(f) = 1.86^(@)C kg mol e^(-1) )