The slopes of lines represented by `x^2+2hxy+2y^2=0` are in the ratio `1:2`, then h equals .

The slopes of the lines represented by x^(2) + 2hxy + 2y^(2) = 0 are in the ratio 1 : 2, then find 'h'.

If the slopes of the lines represented by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2 then h=

Find the value of h if the slopes of the lines represented by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2.

If the slopes of the lines represented by ax^(2)+2hxy+by^(2)=0 are in the ratio m:n then ((m+n)^(2))/(mn)=

If the slopes of the line given by 6x^(2)+2hxy+y^(2)=0 are in the ratio 1:2 , then h=

If the slopes of the lines 3x^(2) + 2hxy + 4y^(2)=0 are in the ration 3:1 , then h equals

If the slopes of the lines given by ax^(2)+2hxy+by^(2)=0 are in the ratio 3:1 , then h^(2)=

If the slopes of the lines given by ax^(2)+2hxy+by^(2)=0 are in the ratio 3:1 , then h^(2)=

If h^(2)=ab then slopes of lines ax^(2)+2hxy+by^(2)=0 are in the ratio