" 17.afe "3cos A=5sin A" in "(5sin A-3cos A)/(5sin A+3cos A)

If 5tan A=3 then (5sin A-2cos A)/(sin A+2cos A) is

( sin A + sin 5A + sin 9A)/( cos A + cos 5A + cos 9A)=

3cos x+4sin x=5

Prove that: (cos 2A cos 3A-cos 2A cos 7A + cos A cos 10A)/(sin 4A sin 3A -sin 2A sin 5A + sin 4A sin 7A)= cot 6A cot 5A .

( sin 4 A sin 3A - sin 5A sin 2A+ sin 7A sin 4A )/(cos 2A cos 3A - cos 2A * cos 7A + cos A * cos 10A )=

Prove that: (cos 2A cos 3A -cos 2A cos 7A + cos A cos 10A)/("sin" 4A sin 3A - sin 2A sin 5A + sin 4A sin 7A) = cot 6A cot 5A

(cos5A+cos3A+cosA)/(sin5A-sin3A+sinA)=

( sin A + sin 3A + sin 5A + sin 7A)/(cos A + cos 3 A + cos 5 A + cos 7A) = tan 4A.

If 5tan theta=4 then value of ((5sin theta-3cos theta)/(5sin theta+3cos theta))=

(sin A sin2A + sin3A sin6A) / (sin A cos2A + sin3A cos6A) = tan5A