In the given figure, in `Delta ABC, angle B= angle C and BD= CE`. Prove that `DE||BC`.

In the given figure , if AB = BC , angle BAD = angle CAE then prove that triangle ADE is an isosceles triangle .

In the given figure, angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE) prove that Delta ACB~ Delta DCE .

In the adjacent figure, Delta ABC is right angled at C and DE bot AB . Prove that Delta ABC ~ Delta ADE and hence find the lengths of AE and DE ?

In the given figure, (AD)/(DB)=(AE)/(EC) and angle ADE=angle ACB . Prove that Delta ABC is an isosceles triangle.

In the given figure , BC = CE and angle 1 = angle 2. Prove that : Delta GCB = Delta DCB .

In the given figure , AB = CD , CE = BF and angle ACE = angle DBF . Prove that triangle ACE cong triangle DBF

In the figure given below ABC is a triangle right angled at A and AC bot BD . Show that AB^(2) = BC xx BD

In the given figure, if angle ADE= angle B , show that Delta ADE~ Delta ABC . If AD=3.8 cm, AE=3.6 cm, BE=2.1 cm, and BC =4.2 cm , find DE.

In the figure given below ABC is a triangle right angled at A and AC bot BD . Show that AD^(2) = BD xx DC

In the given figure, Delta ABC and Delta AMP are right- angled at B and M respectively. Prove that (i) Delta ABC ~~Delta AMP (ii) (CA)/(PA)=(BC)/(MP)