[" Will tind the auve paring through the "],[" point "(1,-1)" having its differential "],[" enuation."quad xydy=(n+2)(y+2)" ."]

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1

If the curve y=f(x) passing through the point (1,2) and satisfies the differential equation xdy+(y+x^(3)y^(2))dx=0 ,then

The equation of the curve through the point (1,0) which satisfies the differential equatoin (1+y^(2))dx-xydy=0 , is

The equation of the curve through the point (1,0) which satisfies the differential equatoin (1+y^(2))dx-xydy=0 , is

Solve the following differential equations 2xydy=(y^(2)-x^(2))dx

Solve the following differential equations 2xydy=(y^(2)-x^(2))dx