" (i) "x^(2)+y^(2)=a^(2)

The ends of hypotenuse of a right angled triangle are (a,0),(-a,0) then the locus of third vertex is a) x^(2)-y^(2)=a^(2) b) x^(2)+y^(2)=a^(2) c) x^(2)+y^(2)+a^(2)=0 d) x^(2)-y^(2)+a^(2)=0

The locus of a point,from where the tangents to the rectangular hyperbola x^(2)-y^(2)=a^(2) contain an angle of 45^(0), is (x^(2)+y^(2))^(2)+a^(2)(x^(2)-y^(2))=4a^(2)2(x^(2)+y^(2))^(2)+4a^(2)(x^(2)-y^(2))=4a^(2)(x^(2)+y^(2))^(2)+4a^(2)(x^(2)-y^(2))=4a^(2)(x^(2)+y^(2))+a^(2(x^(2)-y^(2)))=a^(4)

Find the angle between the curves x^(2)-y^(2)= 2a^(2) and x^(2)+y^(2)=4a^(2)

Acute angle between two curve x^(2)+y^(2)=a^(2)sqrt2 and x^(2)-y^(2)=a^(2) is

Acute angle between two curve x^(2)+y^(2)=a^(2)sqrt2 and x^(2)-y^(2)=a^(2) is

Acute angle between two curve x^(2)+y^(2)=a^(2)sqrt2 and x^(2)-y^(2)=a^(2) is

Add : x^(2) y^(2) , 2x^(2)y^(2) , - 4x^(2)y^(2) , 6x^(2)y^(2)