A potentiometer circuit shown in the figure is set up to measure e.m.f. of a cell E . As the point P moves from X to Y the galvanometer G shows deflection always in one direction, but the deflection decreases continuously until Y is reached. In order to obtain balance point between X and Y it is necessary to

A potentiometer experiment is set up to compare the e.m.f.'s E_(1) and E_(2) of two cells. When the null point is obtained, the current is drawn from

In the circuit shown in figure, the equivalent capacitance between the points X and Y is

In the circuit shown in figure, the equivalent capacitance between the points X and Y is

In the circuit shown in the figure, AB is a resistance wire of uniform cross-section in which a potential gradient of 0.01V^-1 exists. If the galvanometer G shows zero deflection what is the e.m.f. E_1 of the cell used?

A potentiometer experiment is setup as shown in fig. If both the galvanometer shows null deflections for the sliding contacts at x and y as shown then-

A potentiometer is used for the compaisem of e.m.f. of two cells E_(1) and E_(2) . For cell E_(1) the no deflection point os obtained at 20 cm and for E_(2) the no deflection point is obtained at 30 cm . The ratio of their e.m.f.'s will be

A potentiometer is used for the compaisem of e.m.f. of two cells E_(1) and E_(2) . For cell E_(1) the no deflection point os obtained at 20 cm and for E_(2) the no deflection point is obtained at 30 cm . The ratio of their e.m.f.'s will be

While doing an experiment with potentiometer (see figure) it was found that the deflection is one sided and (i) the deflection decreased while moving from one and A of the wire, to the end R, (ii) the deflection increased, while the jockey was moved towards the end D. (a)Which terminal positive and negative of the cell E_1 is connected at X in case (i) and how is E_1 related to E ? (b)Which terminal of the cell E_1 is connected at X in case (i in a) ?