Suppose the sides of a triangle from a geometric progression with conmen ratio `r`. Then `r` lies in the interval

Suppose the sides of a triangle form a geometric progression with common ratio r. Then r lies in the interval-

The sides of a triangle are in geometric progression with common ratio r lt 1. If the triangle is a right-angled triangle, then r is given by

The sides of a triangle are in geometric progression with common ratio rgt1 . If the triangle is a right angled triangle, then r^(2) is given by ?

If the altitudes of a triangle are in arithmetic progression, then the sides of the triangle are in

The sides of a triangle ABC are in GP.Ifr is the common ratio then r lies in the interval

The altitudes of a triangle are in arithmetic progression, then the sides of a triangle are in

Three numbers are in an increasing geometric progression with common ratio r. If the middle number is doubled, then the new numbers are in an arithmetic progression with common difference d. If the fourth term of GP is 3 r^(2) , then r^(2) - d is equal to :

If the sides of a triangles are 3:7:8, then ratio R:r

Let a_(1), a_(2), a_(3) be three positive numbers which are in geometric progression with common ratio r. The inequality a_(3) gt a_(2)+2a_(1) holds true if r is equal to