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[" 10.Latimer diagram for Cu in an acidi...

[" 10.Latimer diagram for Cu in an acidic solution is "],[qquad [Cu^(2+)-+0.15v,>Cu^(+)-(1050V)/(-)Cu*" Find "E_(Cv^(2)+1Cu)^(0)],[(1)+0.65" volt "," (2) "+0.325" volt "],[" (3) "-0.0325" volt "," (4) "-0.325" volt "]]

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Latimer diagram for Cu in an acidic solution is: Cu^(+2) overset(+0.15V)toCu^(+) overset(+0.50)toCu,

Explain why the stability of Cu^(+) io in aqueous solution is lower Cu^(2+) ion . E_(Cu^(2+)|Cu)^(@)= +0.34 "V & "E_(Cu^(+)|Cu)^(@)= +0.52 V

E_(Cu^(2+)//Cu)^(@) =0.43V E_(Cu^(+)//Cu)^(@)=0.55V E_(Cu^(2+)//Cu^(+))^(@) =

Calculate the emf of the given cell: Cu/ Cu^(2+)(0.01M) ∣∣ Cu^(2+) (0.001M)∣Cu is ( E^(@)Cu^(2+) /Cu=+0.34V)

Given , Cu^(2+) + e^(-) to Cu^(+) E^(@) = 0.15 " volt " , Cu^(+) + e^- to Cu E^(@) = 0.5 volt Calculate potential for Cu^(2+) + 2e^(-) to Cu

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

E_(Cu^(2+)//Cu)^(@)=0.34V E_(Cu^(+)//Cu)^(@)=0.522V E_(Cu^(2+)//Cu^(+))^(@)=

If E_(Cu^(2+)|Cu)^(@) = 0.34V and E_(Cu^(2+)|Cu^(+))^(@)= 0.15 V then the value for disproportion for Cu^(+) is :

If E_(Cu^(2+)|Cu)^(@) = 0.34V and E_(Cu^(2+)|Cu^(+))^(@)= 0.15 V then the value for disproportion for Cu^(+) is :