Due to a charge inside the cube, the electric field is: `E_(x)` = 600x, `E_(y)` = 0, `E_(z)` = 0. The charge inside the cube is nearly -

Due to a charge inside a cube the electric field is E_(x)=600 x^(1//2), E_(y)=0, E_(z)=0 . The charge inside the cube is (approximately):

Due to a charge inside a cube the electric field is E_(x)=600 x^(1//2), E_(y)=0, E_(z)=0 . The charge inside the cube is (approximately):

Due to a charge inside a cube the electric field is E_(x)=600 x^(1//2), E_(y)=0, E_(z)=0 . The charge inside the cube is (approximately):

A cube of side a is placed such that the nearest face , which is parallel to the yz plane , is at a distance a from the origin . The electric field components are E_(x) = alpha x ^(1//2) , E_(y) = E_(z) = 0 . The charge within the cube is

A cube of side a is placed such that the nearest face , which is parallel to the yz plane , is at a distance a from the origin . The electric field components are E_(x) = alpha x ^(1//2) , E_(y) = E_(z) = 0 . The charge within the cube is

If the electric field components due to electric charge in cube shown in figure are E_x = 600x^(1/2) and E_y = 0 and E_z = 0 , then charge within the cube…………

A cube is arranged such that its length, breadth and height are along X, Y and Z directions, One of its corners is situated a the origin. Length of each side of the cube is 25cm. The components of electric field are E_(x) = 400 sqrt2 N//C, E_(y) = 0 and E_(z)= 0 respectively. Find the flux coming out of the cube at one end.

A cube is arranged such that its length, breadth and height are along X,Y and Z directions. One of its corners is situated at the origin Length of each side of the cube is 25 cm. The components of electric field are E_(x) = 400 sqrt(2) N//C, E_(y) = 0 and E_(z) = 0 respectively. The flux coming out of the cube at one end will be