The energy required in ionise a helium atom is equal to `24.6 eV` The energy required to remove both the electron from the helium atom would be

The ionisation energy of an electron in the ground state of helium atom is 24.6eV. The energy required to remove both the electron is

The binding energy of the electron in the ground state of He atom is equal to E_(0)=24.6 eV . Find the energy required to remove both the electrons from the atom.

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom ompletelyis:

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom completely is:

The energy required to remove the electron from a singly ionized Helium atom is 2.2 times the energy required to remove an electron from Helium atom. The total energy required to ionize the Helium atom ompletelyis:

The binding energy of an electron in the ground state of He is equal to 24.6 eV: Find the energy required to remove both electrons.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.