x^(2)+6x+5=0

The maximum possible number of real roots of the equation x^(5)-6x^(2)-4x+5=0 is

Find the maximum possible number of real roots of the equation. x^(5)-6x^(2)-4x+5=0 .

The length of the latus rectum of the parabola x^(2)-6x+5y=0 is

x^(4)+4x^(3)+6x^(2)+4x+5=0 one root being sqrt(-1)

Solve by the method of completing the square: (1) 9x^(2)-15x+6=0 (2) 5x^(2)-6x-2=0

Find the locus of a point which moves so that the ratio of the lengths of the tangents to the circles x^(2)+y^(2)+4x+3=0 and x^(2)+y^(2)-6x+5=0 is 2:3

Real roots of the equation x^(2)+6|x|+5=0 are

the equation whose roots are multiplied by -3 of those of 9x^(2)-6x^(2)+5x-4=0 is