A bus starts from rest with a constant acceleration of `5 m//s^(2)` at the same time a car travelling with a constant velocity `50 m//s` over takes and passes the bus. How fast is the bus travelling when they are side by side?

A bus starts from rest with a constant acceleration of 5m/s^2 . At the same time , a car travelling with a constant velocity of 50m/s overtakes and passes the bus ,find (i)at what distance will the bus overtake the car ? (ii)How fast will the bus overtakes the car after distance S metres.

A bus starts from rest with constant acceleration of 5 ms^–2 . At the same time a car travelling with a constant velocity of 50 ms^–1 overtakes and passes the bus. (i) Find at what distance will the bus overtake the car ? (ii) How fast will the bus be travelling then ?

A bus starts from rest and moves with constant acceleration 8 m//s^(2) . At the same time, a car traveling with a constant velocity 16 m//s overtakes and passes the bus. After how much time and at what distance the bus overtakes the car?

A bus starts from rest with an acceleration of 1 m//s^(2) A man who is 48 m behind the bus starts with a uniform velocity of 10 m s^(-1) . Then after how much time the man will catch the bus ?

A bus starting from rest moves with a uniform acceleration of 0.1 ms^-2 for two minutes. The distance travelled.