If `ax^2+bx+c=0` has imaginary roots and `a,b,c in R`such that `a+4c<2b` then

If ax^(2)+bx+c = 0 has no real roots and a, b, c in R such that a + c gt 0 , then

If ax^(2)+bx+c = 0 has no real roots and a, b, c in R such that a + c gt 0 , then

if ax^(2)+bx+c=0 has imaginary roots and a+c

if ax^2+bx+c = 0 has imaginary roots and a+c lt b then prove that 4a+c lt 2b

if ax^2+bx+c = 0 has imaginary roots and a+c lt b then prove that 4a+c lt 2b

if ax^2+bx+c = 0 has imaginary roots and a+c lt b then prove that 4a+c lt 2b

If ax^(2) + bx + c = 0 has imaginary roots and a - b + c gt 0 . then the set of point (x, y) satisfying the equation |a (x^(2) + (y)/(a)) + (b + 1) x + c| = |ax^(2) + bx + c|+ |x + y| of the region in the xy- plane which is

If y=f(x)=ax^(2)+2bx+c=0 has Imaginary roots and 4a+4b+c<0 then

Statement- 1 : If a,b,c in R-{0} , then at least one ax^(2)+bx+c=0 , bx^(2)+cx+a=0 and cx^(2)+ax+b=0 has imaginary roots. Statement- 2 : If a,b,c in R,a!=0 , then imaginary roots of the equation ax^(2)+bx+c=0 occur in conjugate pair.Then