[" 42."x" ) "(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)],[(7)/((2x+3y))+(4)/((3x-2y))=2],[2x+3y!=0],[3x-2y!=0]Solve for more.

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0

Solve [2x+3y-7=0],[3x+2y-8=0]

Solve for x and y (2)/(x)+(2)/(3y)=(1)/(6),(3)/(x)+(2)/(y)=0

3x + 2y = 0, x + 3y = 7

Solve the following pairs of equations by reducing them to a linear pair :- 1/(2(2x+3y))+12/(7(3x-2y))=1/2, 7/(2x+3y)+4/(3x-2y)=2 .

3x+2y=5 2x+3y=7

3x+2y=5 2x-3y=7

(2x^2+3y^2-7)x dx-(3x^2+2y^2-8)y dy=0

(2x^2+3y^2-7)x dx-(3x^2+2y^2-8)y dy=0