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[" A.Isomerism "(" B Polymorphism ")/(" concentration of catio ")],[" AaCl is doped with "(2times10^(-3)mol%SrCl_(2))/(" B."10.01times10^(18)mol')],[" (A) "12.04times10^(18)mol^(-1)],[" C."12.04times10^(20)mol^(-1)]

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What is the concentration of cation vacancies if NaCl is doped with 10^(-3) mol percent of MgCl_(2) ?

If NaCl is doped with 10^(-3) mol % of SrCl_(2) , What is the concentration of cation valencies ?

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-4)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(-8)mol% of SrCl_(2) the concentration of cation vacancies will be (N_(A)=6.02xx10^(23)mol^(-1))

If NaCl is doped with 10^(4) mol % of SrCl_(2) the concentration of cation vacancies will be (N_(A) = 6.02 xx 10^(23) mol^(-1))

Simplify: 10^(-1)times10^(2)times10^(-3)times10^(4)times10^(-5)times10^(6)