Find the general solution of `sinx=tanx`

Explanation

`sin x=tanx`
`therefore sinx=(sinx)/(cosx)`
`therefore sinx cosx=sinx`
`therefore sinxcosx-sinx=0`
`therefore sinx(cosx-1)=0`
`therefore` either `sinx=0` or `cosx-1=0`
`therefore` either `sinx=0` or `cosx=1`
`therefore` either `sinx=0` or `cosx=cos0`
The general solution of `sintheta =0` is `theta=n pi, n in Z` and `costheta=cosalpha` is `theta = 2n pi +-alpha`, where `n in Z`.
`therefore` the requried general solution is given by `x= n pi , n in Z or x =2 n pi +-0,n in Z`
`therefore x= n pi, n in Z or x =2 n pi , n in Z`.