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In a triangle ABC , with usual notations...

In a `triangle ABC` , with usual notations , prove that `(a-bcosC)/(b-acosC)=(cosB)/(cosA)`.

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To prove the identity \(\frac{a - b \cos C}{b - a \cos C} = \frac{\cos B}{\cos A}\) in triangle \(ABC\), we will start with the left-hand side (LHS) and manipulate it to show that it equals the right-hand side (RHS). ### Step-by-Step Solution: 1. **Start with the LHS**: \[ \text{LHS} = \frac{a - b \cos C}{b - a \cos C} \] ...
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