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Find the vector equation of a line...

Find the vector equation of a line which passes through the point with position vector ` 4hati - hatj + 2 hatk ` and is in the direction of ` - 2 hati + hatj + hatk `.

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The vector equation of the line passing through ` A ( bar a ) ` and parallel to ` bar b ` is
` bar r = bar a + lamda bar b ` , where ` lamda ` is a scalar.
Here ` bar a = 4 hati - hatj + 2hatk and bar b = - 2 hati + hatj + hatk `
` therefore ` vector equation of the required line is ` bar r = ( 4 hati - hatj + 2 hatk ) + lamda ( - 2 hati + hatj + hatk ) `
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