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Find the direction cosines of the line ` ( x + 2 ) /(2) = ( 2 y - 5) /( 3 ) , z = - 1 `

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The equation of the line is ` ( x + 2 ) /( 2 ) = ( 2y - 5) /(3) , z = - 1 `
` therefore ( x + 2) /(2) = ( 2 ( y - ( 5 ) /(2)) ) /( 3 ) , z = - 1 `
` therefore ( x + 2 ) /( 2 ) = ( y - ( 5 ) /(2) ) /( ((3 ) / ( 2 ) ) ) , z = - 1 `
` therefore ` the direction ratios of the line are ` 2, (3) /(2), 0, ` i.e., ` 4, 3, 0 `
` therefore ` the direction cosines of the line are ` ( 4 ) /(sqrt ( 4 ^2 + 3^2 + 0 ) ) , ( 3 ) /(sqrt( 4 ^2 + 3^2 + 0)) , 0 `
i.e., ` ( 4 ) /(5), ( 3 ) /(5), 0 `.
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