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Equation of the line passing through the...

Equation of the line passing through the point ( 2,3, -4) and perpendicular to XZ-plane is

A

`bar(r) = (3hati + 4hatj - 7hatk) + lamda (2hati + 3hatj + 13hatk)`

B

`bar(r) = (3hati + 4hatj - 7hatk) + lamda (8hati + 5hatj + hatk)`

C

`bar(r) = (3hati + 4hatj - 7hatk) + lamda (2hati - 3hatj - k)`

D

`bar(r) = (3hati + 4hatj - 7hatk) + lamda (2hati - 3hatj - 13hatk)`

Text Solution

Verified by Experts

The correct Answer is:
(b) x = 2 , y = 3 + lamda , z = -4
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Knowledge Check

  • The equation of the line passing through the point (3,0,-4) and perpendicular to the plane 2x-3y+5z-7=0 is

    A
    `(x-2)/3=y/-3=(z+4)/5`
    B
    `(x-3)/2=y/-3=(z-4)/5`
    C
    `(x-3)/2=(-y)/3=(z+4)/5`
    D
    `(x+3)/2=y/3=(z-4)/5`

  • The equation of line passing through the point (2, 3, 4) and perpendicular to plane 2x+3y+z+5=0 is

    A
    `(x-2)/(1)=(y-3)/(2)=(z-4)/(3)`
    B
    `(x-2)/(3)=(y-3)/(2)=(z-4)/(1)`
    C
    `(x-2)/(2)=(y-3)/(3)=(z-4)/(1)`
    D
    `(x-2)/(1)=(y-3)/(3)=(z-4)/(2)`

  • The equation of the line passing though the point (1,1,-1) and perpendicular to the plane x -2y - 3z =7 is :

    A
    `(x-1)/(-1) = (y-1)/(2) = (z+1)/(-3)`
    B
    `(x-1)/(-1) = (y-1)/(-2) = (z+1)/(3)`
    C
    `(x-1)/(1) = (y-1)/(-2) = (z+1)/(-3)`
    D
    None of these

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    The equation of a line passing through point (2,3,-1) and perpendicular to ZX plane is

    The equation of a line passing through point (2,3,-1) and perpendicular to XY plane is

    Equation of the plane passing through point P(a,b,c) and perpendicular to OP is

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