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tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(...

`tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))`

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To solve the problem \( y = \tan^{-1}\left(\frac{\sqrt{1+x^2} + \sqrt{1-x^2}}{\sqrt{1+x^2} - \sqrt{1-x^2}}\right) \) and find \( \frac{dy}{dx} \), we can follow these steps: ### Step 1: Substitute \( x = \cos(2\theta) \) Let \( x = \cos(2\theta) \). Then, we can express \( x^2 \) as \( \cos^2(2\theta) \). ### Step 2: Rewrite the expression ...
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int(sqrt(1-x^(2))+sqrt(1+x^(2)))/(sqrt(1-x^(2))sqrt(1+x^(2)))dx=

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Knowledge Check

  • The derivative of tan^(-1)((sqrt(1 + x)-sqrt(1-x))/(sqrt(1 + x)+sqrt(1-x))) is

    A
    `sqrt(1 - x^(2))`
    B
    `(1)/(sqrt(1-x^(2)))`
    C
    `(1)/(2sqrt(1-x^(2)))`
    D
    x
  • The differential coefficient of tan^(-1)((sqrt(1+x)-sqrt(1-x))/(sqrt(1+x)+sqrt(1-x))) , is

    A
    `sqrt(1-x^2)`
    B
    `1/(sqrt(1-x^2))`
    C
    `1/(2sqrt(1-x^2))`
    D
    x
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