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tan^(-1)((x)/(sqrt(1-x^(2))))"w.r.t."sec...

`tan^(-1)((x)/(sqrt(1-x^(2))))"w.r.t."sec^(-1)((1)/(2x^(2)-1))`

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To solve the problem of finding the derivative of \( u = \tan^{-1}\left(\frac{x}{\sqrt{1-x^2}}\right) \) with respect to \( v = \sec^{-1}\left(\frac{1}{2x^2 - 1}\right) \), we will use the chain rule and implicit differentiation. ### Step-by-Step Solution: 1. **Define the Functions**: Let \( u = \tan^{-1}\left(\frac{x}{\sqrt{1-x^2}}\right) \) and \( v = \sec^{-1}\left(\frac{1}{2x^2 - 1}\right) \). 2. **Differentiate \( u \) with respect to \( x \)**: ...
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Differentiate w.r.t. as indicated : tan^(-1)(x/(sqrt(1-x^(2))))" w.r.t. "sin^(-1)(2xsqrt(1-x^(2))) .

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Knowledge Check

  • Derivative of tan^(-1)2xsqrt(1-x^(2))/(1-2x^(2))w.r.t.sec^(-1)" "(1)/(2x^(2)-1)" at "x=(1)/(2)

    A
    `(1)/(2)`
    B
    `-(1)/(2)`
    C
    `-1`
    D
    1
  • Darivative of tan ^(-1) ((x)/( sqrt(1-x^(2)))) w.r.t. sin ^(-1) (3x -4x^(3)) is

    A
    ` (1)/(sqrt( 1-x^(2))) `
    B
    ` (3)/(sqrt( 1-x^(2)))`
    C
    ` 3`
    D
    `(1)/(3)`
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