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(sinx)^(x)...

`(sinx)^(x)`

A

`(sinx)^(x)[cotx+logsinx]`

B

`(sinx)^(2)[xcotx+logsinx]`

C

`sinx[xcotx+logsinx]`

D

`(sinx)^(x)[xcotx+logsinx]`

Text Solution

Verified by Experts

The correct Answer is:
D
`(sinx)^(x)[xcotx+logsinx]`
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