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cos^(-1).((2x)/(1+x^(2)))...

`cos^(-1).((2x)/(1+x^(2)))`

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To differentiate the function \( y = \cos^{-1}\left(\frac{2x}{1+x^2}\right) \), we will follow these steps: ### Step 1: Substitute \( x = \tan(\theta) \) Let \( x = \tan(\theta) \). Then we can rewrite the expression inside the inverse cosine function: \[ y = \cos^{-1}\left(\frac{2\tan(\theta)}{1+\tan^2(\theta)}\right) ...
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