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y=cos^(-1)((3cosx-4sinx)/(5)), then (dy)...

`y=cos^(-1)((3cosx-4sinx)/(5))`, then `(dy)/(dx)=`

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To find the derivative of the function \( y = \cos^{-1}\left(\frac{3\cos x - 4\sin x}{5}\right) \), we will follow these steps: ### Step 1: Differentiate using the chain rule We know that the derivative of \( \cos^{-1}(u) \) is given by: \[ \frac{dy}{dx} = -\frac{1}{\sqrt{1 - u^2}} \cdot \frac{du}{dx} \] where \( u = \frac{3\cos x - 4\sin x}{5} \). ...
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Knowledge Check

  • If y=cos^(-1)((2cosx-3sinx)/(sqrt(13))) , then (dy)/(dx) , is

    A
    zero
    B
    constant=1
    C
    `"constant "ne1`
    D
    none of these
  • If y=cos^(-1)((4cos x-5sinx)/(sqrt(41))) , then (dy)/(dx) is equal to

    A
    0
    B
    1
    C
    `-1`
    D
    none of these
  • If y=tan^(-1)[(sinx+cosx)/(cosx-sinx)] then (dy)/(dx) is

    A
    `1/2`
    B
    `(pi)/4`
    C
    0
    D
    1
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