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xy+ysec^(-1)x=1...

`xy+ysec^(-1)x=1`

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To differentiate the equation \( xy + y \sec^{-1} x = 1 \), we will use implicit differentiation. Here are the steps: ### Step 1: Differentiate both sides We start by differentiating both sides of the equation with respect to \( x \): \[ \frac{d}{dx}(xy + y \sec^{-1} x) = \frac{d}{dx}(1) \] Since the derivative of a constant is zero, we have: ...
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