The displacement x of a particle at time...

The displacement x of a particle at time t is given by `x=160t-16t^(2)`. Show that its velocity at t = 1 amd t = 9 are equal in magnitude but opposite in directions.

Topper's Solved these Questions

APPLICATIONS OF DERIVATIVES
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise MULTIPLE CHOICE QUESTIONS|12 Videos
APPLICATIONS OF DERIVATIVES
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise MULTIPLE CHOICE QUESTIONS|12 Videos
APPLICATIONS OF DEFINITE INTEGRALS ( AREA )
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise EXAMPLES FOR PRACTICE (3 OR 4 MARKS )|5 Videos
BINOMIAL DISTRIBUTION
NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise MULTIPLE CHOICE QUESTIONS|8 Videos

Similar Questions

Explore conceptually related problems

The displacement x of a particle at a time t is given by x=160t-16t^(2) ,show that its velocity at t=1 and t=9 are equal in magnitude but opposite in direction.

The displacement of a particle in time t is given by s=2t^2-3t+1 . The acceleration is

The displacement s of a particle at a time t is given bys =t^(3)-4t^(2)-5t. Find its velocity and acceleration at t=2 .

If displacements of a particle varies with time t as s = 1/t^(2) , then.

The displacement of a particle along the x-axis is given by x=3+8t+7t^2 . Obtain its velocity and acceleration at t=2s .

The displacement x of a particle moving along x-axis at time t is given by x^2 =2t^2 + 6t . The velocity at any time t is

The displacement s of a moving particle at a time t is given by s=5+20t-2t^(2) . Find its acceleration when the velocity is zero.

For a particle moving in a straight line, the displacement of the particle at time t is given by S=t^(3)-6t^(2) +3t+7 What is the velocity of the particle when its acceleration is zero?

The displacement x of a particle in a straight line motion is given by x=1-t-t^(2) . The correct representation of the motion is

If displacement of particle is x=160t-16t^(2) , then at t=1and t=9, velocities are

NAVNEET PUBLICATION - MAHARASHTRA BOARD-APPLICATIONS OF DERIVATIVES -Examples for Practice

The displacement s of a particle at a time t is given by s = t^3 - 4t...
Text Solution
|
A particle moves according to law s=t^(3)-6t^(2)+9t+15. Find the veloc...
Text Solution
|
The displacement x of a particle at time t is given by x=160t-16t^(2)....
Text Solution
|
The side of a square is increasing at the rate of 0.5 cm/sec. Find the...
Text Solution
|
The radius of a circular blot of oil is increasing at the rate of 2 cm...
Text Solution
|
The radius of a circular blot of oil is increasing at the rate of 2 cm...
Text Solution
|
A spherical snow ball is melting so that its volume is decreasing at t...
Text Solution
|
A man of 2 metres height walks at a uniform speed of 6 km/hr away from...
Text Solution
|
Aladder of 5 m long rest with one end against a vertical wall of heigh...
Text Solution
|
If the volume of spherical ball is increasing at the rate of 4pi" cc/s...
Text Solution
|
Sand is pouring from a pipe at the rate of 12 c m^3//s . The falling s...
Text Solution
|
Water is being poured at the rate of 36" m"^(3)//"sec" in a cylindrica...
Text Solution
|
Find the approximate values of : (4.01)^(5)
Text Solution
|
Find the approximate values of : sqrt(144.02)
Text Solution
|
Find the approximate values of : root(3)(26.96)
Text Solution
|
Find the approximate values of : f(x)=x^(3)+5x^(2)-7x+10" at "x=1.1...
Text Solution
|
Find the approximate values of : cos(60^(@)30')," given "1^(@)=0.01...
Text Solution
|
The apprximate value of sin(31^(@)), given that 1^(@)=0.0175, cos 30^(...
Text Solution
|
Find the approximate values of : tan(44^(@))," given "1^(@)=0.0175^...
Text Solution
|
Approximate value of tan^(-1)(0.999) is
Text Solution
|