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y = log x + c is a solution of the diff...

`y = log x + c ` is a solution of the differential equation ` x(d^(2)y)/(dx^(2)) + (dy)/(dx) = 0`

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To verify that \( y = \log x + c \) is a solution of the differential equation \[ x \frac{d^2y}{dx^2} + \frac{dy}{dx} = 0, \] we will follow these steps: ...
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