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y-x(dy)/(dx)=a(y^2+(dy)/(dx))...

`y-x(dy)/(dx)=a(y^2+(dy)/(dx))`

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` y-x (dy)/(dx) =a (y^(2) + dy/dx) " " therefore y -x (dy)/(dx) =ay^(3) +a (dy)/(dx)`
` y -ay^(2) = x(dy)/(edx) + a (dy)/(dx) " " therefore y(1 -ay) = (x + a) (dy)/(dx)`
` (dx)/(x+a) = (dy)/(y(1 -ay))`
` int (dx)/(x +a) - int (dy)/(y(1-ay)) =c_(1)`
`int(dy)/(y (1-ay)) = int ((1-ay)+ay)/(y(1-ay))=dy = int (1/y + a/(1-ay))dy `
`log|y| +a (log|1-ay|)/(-a)= log |y| - log | 1 -ay| = log |y/(1-ay)|`
(1) gives, ` log |x +a| - log |y/(1-ay)| = log c, " where " c_(1) =log c`
`log |((x+a)(1-ay))/y| = log c " " therefore ((x+a)(1-ay))/y = c `
(x+a) (1-ay) =cy is the general solution.
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