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(dy)/(dx) =e^(2y) cos x, " when " x = pi...

`(dy)/(dx) =e^(2y) cos x, " when " x = pi/6, y = 0`

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To solve the differential equation \(\frac{dy}{dx} = e^{2y} \cos x\) with the initial condition \(x = \frac{\pi}{6}\) and \(y = 0\), we can follow these steps: ### Step 1: Rearranging the Equation We start with the given equation: \[ \frac{dy}{dx} = e^{2y} \cos x \] We can rearrange this to separate the variables \(y\) and \(x\): ...
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