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A body is heated to 110^(@)C and placed ...

A body is heated to `110^(@)C` and placed in air at ` 10^(@)C`. After 1 hour its temperature is `60^(@)C` . How much additional time is required for it to cool to `35^(@)C ` ?

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To solve the problem of how much additional time is required for a body to cool from 60°C to 35°C after being heated to 110°C and placed in air at 10°C, we will use Newton's Law of Cooling. ### Step-by-Step Solution: 1. **Understanding the Law**: According to Newton's Law of Cooling, the rate of change of temperature of an object is proportional to the difference between its own temperature and the ambient temperature. The formula is given by: \[ \frac{dT}{dt} = -k(T - T_0) \] ...
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