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(1) y = ae^(4x) -be^(-3x) +c (2) xy = ...

`(1) y = ae^(4x) -be^(-3x) +c (2) xy = ae^(5x) +be^(-5x)`

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The correct Answer is:
(1) `(d^(3)y)/(dx^(3)) -(d^(2)y)/(dx^(2)) -12(dy)/(dx)=0` (2) `x(d^(3)y)/(dx^(2)) +2(dy)/(dx) = 25 xy `
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(1)/(ae^(x)+be^(-x))

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