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The differential equation of y = c^(2) ...

The differential equation of ` y = c^(2) + c/x` is

A

`x^(4) ((dy)/(dx))^(2) - x(dy)/(dx) =y`

B

`(d^(2)y)/(dx^(2)) +x (dy)/(dx) + y=0`

C

` x^(3)((dy)/(dx))^(2) + x(dy)/(dx) = y`

D

`(d^(2)y)/(dx^(2)) + (dy)/(dx) -y=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the differential equation of the given function \( y = c^2 + \frac{c}{x} \), we will follow these steps: ### Step 1: Differentiate the equation with respect to \( x \) Given the equation: \[ y = c^2 + \frac{c}{x} \] We differentiate both sides with respect to \( x \): \[ \frac{dy}{dx} = 0 + \frac{d}{dx}\left(\frac{c}{x}\right) \] Using the quotient rule, we get: \[ \frac{dy}{dx} = -\frac{c}{x^2} \] ### Step 2: Express \( c \) in terms of \( y \) and \( x \) From the original equation, we can isolate \( c \): \[ c = x(y - c^2) \] ### Step 3: Substitute \( c \) back into the derivative Now we substitute \( c \) in the derivative equation: \[ \frac{dy}{dx} = -\frac{x(y - c^2)}{x^2} = -\frac{y - c^2}{x} \] This gives us: \[ \frac{dy}{dx} = -\frac{y - c^2}{x} \] ### Step 4: Rearranging the equation Rearranging the equation gives: \[ x \frac{dy}{dx} + y = c^2 \] ### Step 5: Form the differential equation Now we need to eliminate the constant \( c \). From the previous steps, we have: \[ c^2 = x \frac{dy}{dx} + y \] Thus, we can express the differential equation as: \[ x \frac{dy}{dx} + y - c^2 = 0 \] ### Final Differential Equation The final form of the differential equation is: \[ x \frac{dy}{dx} + y = c^2 \]
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