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For the following p.d.f of X, find P(...

For the following p.d.f of X, find `P(X lt 1) and P(|X|le 1)` : `f(x) = {{:((x+2)/(18),-2lt xlt 4),(0,"otherwise"):}`

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To solve the problem, we need to find the probabilities \( P(X < 1) \) and \( P(|X| \leq 1) \) using the given probability density function (p.d.f.): \[ f(x) = \begin{cases} \frac{x + 2}{18} & \text{for } -2 < x < 4 \\ 0 & \text{otherwise} \end{cases} \] ...
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