Home
Class 12
MATHS
The p.d.f of continuous random variable ...

The p.d.f of continuous random variable X is given by `f(x)=x/8,0 lt x lt 4 =0` otherwise. Find (i) `P(X lt 2) (ii) P(2 lt X le 3) ( iii) P( X gt 3.)`

Text Solution

AI Generated Solution

To solve the problem, we will calculate the probabilities step by step using the given probability density function (p.d.f) of the continuous random variable \(X\). The p.d.f is given by: \[ f(x) = \begin{cases} \frac{x}{8} & \text{for } 0 < x < 4 \\ ...
Promotional Banner

Topper's Solved these Questions

  • MODEL QUESTION PAPER FOR PRACTICE

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise SECTION-D (Atempt any five of the following)|8 Videos
  • MODEL QUESTION PAPER FOR PRACTICE

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise SECTION-B (Attempt any Eight of the following )|12 Videos
  • MATRICES

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise MULTIPLE CHOICE QUESTIONS|12 Videos
  • PAIR OF STRAIGHT LINES

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise MULTIPLE CHOICE QUESTIONS|10 Videos

Similar Questions

Explore conceptually related problems

The p.d.f of a continous random variable X is f(x)=x/8, 0 lt x lt 4 =0 , otherwise Then the value of P(X gt 3) is

The p.d.f of a random variable X is given by f(x) = 3(1-2x^(2)), 0 lt x lt 1 = 0 , otherwise Find P((1)/(4)lt X lt (1)/(3))

The p.d.f. of a continuous random variable X is f(x) = K/(sqrt(x)), 0 lt x lt 4 = 0 , otherwise Then P(X ge1) is equal to

If p.d.f, of continuous random variable X is f(x) = {(2x^3,;0 lt= x lt=1), (0,;" otherwise"):}. Find P (X lt= 0.5) and P (0.5 lt= X lt= 1)

The p.d.f of a continuous random variable X is f(x) = (x^(2))/(3), - 1 lt x lt 2 0 = otherwise Then the c.d.f of X is

If the p.d.f of a continuous random variable X is f(x)=kx^(2)(1-x), 0 lt x lt 1 = 0 otherwise Then the value of k is

The p.d.f of a random variable x is given by f(x)=(1)/(4a), 0 lt x lt 4a, (a gt 0) =0, otherwise and P(x lt (3a)/(2))=kP(xgt(5a)/(2) then k= . . .

The following is the p.d.f of continuous random variable X. f(x) = (x)/(8), 0 lt x lt 4 =0 , otherwise. Find the expression for c.d.f of X

The following is the p.d.f of continuous random variable X. f(x) = (x)/(8), 0 lt x lt 4 =0 , otherwise. Also , find its value at x = 0.5 , 1.7 and 5

The p. d. f. of a continuous r. v. Xis f(x) = {:((3x^2)/8 , 0 lt x lt 2),(0, "otherwise"):} Determine the c.d.f of X and hence find (i) P(X lt 1), (ii) P(1 lt X lt 2) .