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trianglePQR~trianglePMN."In" trianglePQR...

`trianglePQR~trianglePMN."In" trianglePQR,PQ=` 4 cm , QR = 5 cm and PR = 6 cm.
Construct `trianglePQR and trianglePMN` such that `(PR)/(PN)=5/3`

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To construct triangles PQR and PMN such that triangle PQR is similar to triangle PMN and the ratio \( \frac{PR}{PN} = \frac{5}{3} \), follow these steps: ### Step-by-Step Solution: 1. **Draw Line Segment PR**: - Start by drawing a line segment PR of length 6 cm. Label the endpoints as P and R. - **Hint**: Use a ruler to ensure the line segment is exactly 6 cm long. ...
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