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Four particles of masses 2 kg, 3 kg, 2 k...

Four particles of masses 2 kg, 3 kg, 2 kg and 4 kg are at the corners of a square of diagonal 4 m, as shown. The net gravitational force on a particle of mass 1 kg at the centre of the square is [`"Take "G=(20)/(3)xx10^(-11)" SI units, pN" equiv "piconewton"]`

A

`(5)/(3) pN`

B

`(5)/(6) pN`

C

`(50)/(6) pN`

D

`(50)/(3)` pN.

Text Solution

Verified by Experts

The correct Answer is:
D
The net force on the particle at O,
`vecF_(OD)=vecF_(OA)+vecF_(OC)+vecF_(OD)`
`therefore|vecF_(O)|=F_(OD)-F_(OB)" "(because vecF_(OC)=-vecF_(OA))`
`=(Gm_(O))/(r^(2))(m_(D)-m_(B))=((20)/(3)xx10^(-11))((1)(4-3))/(2^(2))`
`=(50)/(3)xx10^(-12)N=(5)/(3) pN.`
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