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If the width ratio of the two slits in Y...

If the width ratio of the two slits in Young's double slit experiment is 4:1, then the ratio of intensity at the maxima and minima in the interference patternn will be

A

`(221)/(21)`

B

`((221)/(21))^(2)`

C

441

D

121

Text Solution

Verified by Experts

The correct Answer is:
C
`(A_(1))/(A_(2))=sqrt((I_(1))/(I_(2)))=sqrt((w_(1))/(w_(2)))=sqrt(1 cdot 21)=(11)/(10).`
`therefore (I_(max))/(I_(min))=((A_(1)+A_(2))/(A_(1)-A_(2)))^(2)=((11+10)/(11-10))^(2)=21^(2)`
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