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A cube of marble, of volume 1 cm^(3) and...

A cube of marble, of volume `1 cm^(3)` and permittivity 75 pF/m, is in an electric field of intensity 200 V/m. The electrostatic energy in the cube is

A

`1.5xx10^(-12)J`

B

`1.3275xx10^(-11)J`

C

`1.5xx10^(-6)J`

D

`1.3275xx10^(-5)J`

Text Solution

Verified by Experts

The correct Answer is:
A
Energy contained = energy density `xx` volume
`=(1)/(2)epsiE^(2)xxV=(1)/(2)(75xx10^(-12))(4xx10^(4))(10^(-6))=150xx10^(-14)J.`
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