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A circular conducting loop of area 100 c...

A circular conducting loop of area `100 cm^(2)` and resistance `3 Omega` is placed in a magnetic field with its plane perpendicular to the field. If the field is spatially uniform but varies with time t (in second) as `B(t) = 1.5 cos omega t` tesla, the peak value of the current in the loop is

A

3 mA

B

`5 omega mA`

C

`300 omega mA`

D

500 mA

Text Solution

Verified by Experts

The correct Answer is:
B
`E=-(d(BA))/(dt)=-A(dB)/(dt)=1.5 A omega sin omega t =E_(0) sin omega t`
`"Since "A=10^(-2) m^(2), E_(0)=(1.5xx10^(-2))omega V=15 omega mV`
`therefore I_(0)=(E_(0))/(R)=(15omega)/(3)=5 omega mA.`
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