Home
Class 12
PHYSICS
Escape speed....

Escape speed.

Text Solution

Verified by Experts

The escape speed of a statellite is the minimum speed with which it should be projeccted from the orbit , so that it can escape from the Earth's gravitational field.
Promotional Banner

Topper's Solved these Questions

  • DEFINITIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise ROTATIONAL MOTION|3 Videos

  • DEFINITIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise OSCILLATION|8 Videos

  • DEFINITIONS

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise COMMUNICATION SYSTEMS|3 Videos

  • DERIVATIONS-I

    NAVNEET PUBLICATION - MAHARASHTRA BOARD|Exercise Assignments|9 Videos

Similar Questions

Explore conceptually related problems

Calculate the minimum speed required by a rocket to pull out of the gravitational force of Mars. Given that the earth has a mass 9 times and radius twice of the planet Mars. Escape speed on the surface of earth is 11.2 km s^(-1) .

The escape speed from earth's surface is 11kms^(-1) . A certain planet has a radius twice that of earth but its mean density is the same as that of the earth. Find the value of the escape speed from the planet.

Graviational acceleration on the surface of plane fo (sqrt6)/(11)g. where g is the gracitational acceleration on the surface of the earth. The average mass density of the planet is (2)/(3) times that of the earth. If the escape speed on the surface of the earht is taken to be 11 kms^(-1) the escape speed on teh surface of the planet in kms^(-1) will be

The escape speed of a projectile on the earth's surface is 11.2 km s^(-1) . A body is projected out with thrice this speed. What is the speed of the body far away from the earth? Ignore the presence of the sun and other planets.

The escape speed of a particle on the surface of the earth is 11.2km/second. A body is projectwith thrice this speed from the surface of the earth. What is the speed of the body in the outer space far away from the earth?

A satellite is revolving round the earth with orbital speed v_(0) if it is imagined to stop suddenly the speed with which it will strike the surface of the earth would be (v_(e) - escape speed of a body from earth s surface)

Statement I: If a particle projected horizontally just above, the surface of the earth with a speed greater than escape speed, then it will escape from gravitational influence of the earth. Assume that particle has a clear path. Statement II: Escape velocity is independent of its direction.

Does the escape speed of a body from the earth depend on (a) the mass of the body. (b) the location from where it is projected. © the direction of projection, (d) the height of the location from where the body is launched?

Calculate the escape speed for an atmospheric particle 1600 km above the Earth's surface, given that the radius of the Earth is 6400 km amd acceleration due to gravity on the surface of Earth is 9.8 ms^(-2) .