The angle which the free surface of a liquid filled in a container will make with horizontal if the container is accelerated horizontally with acceleration `(g)/(sqrt(3))` is

Explanation

For a molecule in the liquid surface which is in contact with a solid, the forces on it are largely the solid liquid adhesive froce `vecf_(A)` and the liquid-liquid cohesive force `vec_(c.) vecf_(A)` is normal to the solid surface and F is at with the horizontal, Fig. (a). The free surface of a liquid at rest is always perpendicular to the resultant `vecF_(R)` of these forces.
If `F_(C)=sqrt2F_(A),vecF_(R)` along the solid surface, the contact angle is `90^(@)` and the liquid surface is horizontal at the edge where it meets the solid, as in Fig. (a). In general this is not so, and the liquid surface is not horizontal at the edge
If `F_(C)ltsqrt2F_(A) F_(C)ltltF_(A)` or if `F_(C)lt sqrt2F_(A)` the contact angle is correspondingly zero or acute and the liquid surface curves up until it becomes perpendicular to Fig. (b).
If `F_(C)gtsqrt2F(A)` the contact angle is obtuse and the liquid surface curves down until it becomes perpendicular to `vec_(A)`, and acquires a convex shape, Fig. (c).