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Derive an expression for the electric fi...

Derive an expression for the electric field intensity at a point outside a charged conducting sphere.

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To derive the expression for the electric field intensity at a point outside a charged conducting sphere, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Setup**: - Consider a conducting sphere of radius \( R \) with a total charge \( Q \) distributed uniformly over its surface. We want to find the electric field intensity \( E \) at a point outside the sphere at a distance \( r \) from the center of the sphere, where \( r > R \). 2. **Using Gauss's Law**: ...
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Derive an expression for electric field intensity at a point due to point charge.

(a) Using Gauss's law, derive an expression for the electric field intensity at any point outside a uniformly charged thin spherical shell of radius R and charge density sigma C//m^(2) . Draw the field lines when the charge density of the sphere is (i) positive, (ii) negative. (b) A uniformly charged conducting sphere of 2.5 m in diameter has a surface charge density of 100 mu C//m^(2) . Calculate the (i) charge on the sphere (ii) total electric flux passing through the sphere.

Knowledge Check

  • Electric intensity at a point just outside a charged conductor of any shape is

    A
    `sigma/(in_(0)K)`
    B
    `sigma/(2in_(0)K)`
    C
    `(2sigma)/(inK)`
    D
    `(sigma^(2))/(2inK)`
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