Determine the change in wavelength of light during its passage from air to glass, if the refractive index of glass with respect to air is 1.5 and the frequency of light is `3.5 xx 10^(14)` Hz.

Explanation

Data: `n=1.5, v=3.5 xx 10^(14)Hz, c=3 xx 10^(8) m//s`
`lambda_(a) = c/v= (3 xx 10^(8))/(3.5 xx 10^(14)) = 8.571 xx 10^(-7)m = 8571 Å`
`n=lambda_(a)/lambda_(g) therefore lambda_(g)=(8571)/(1.5) = 571 Å`
`therefore` the change in wavelength, `Deltalambda= lambda_(a)-lambda_(g) = 8571- 5714 = 2857 Å`