The magnetic induction at 0.1 m from a very long straight wire carrying a current of 5A is `10^(-6) Wb//m^(2)`. What will be the magnetic induction at 0.2 m from the wire if the current through it is increased to 20 A?

Explanation

`B=(mu_(0))/(4pi) (2I)/r therefore B_(2)/B_(1) = I_(2)/I_(1) xx r_(1)/r_(2) = 20/5 xx 0.1/0.2=2`
`therefore` The required magnetic induction, `B_(2) =2 xx 10^(-5) Wb//m^(2)`