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The strength of the magnetic field in a ...

The strength of the magnetic field in a long solenoid having 5000 turns per meter is `3.14X10^(-2)T`. The current flowing through the solenoid is

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`B=mu_(0)nI therefore` The current in the solenoid,
`I=B/(mu_(0)n) = (3.142 xx 10^(-3))/(4 xx 3.142 xx 10^(-7) xx 500) = 10/20 = 0.5A`
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