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The combined resistance of a galvanome...

The combined resistance of a galvanometer of resistance `500 Omega` and its shunt is `21 Omega` Calculated the value of shunt.

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Data: `G=500 Omega, R_(A)=21 Omega`
`=1/R_(A) = 1/G + 1/S`
`therefore 1/S = 1/R_(A)-1/G=(G-R_(A))/(R_(A).G)`
`therefore` The shunt, `S=(R_(A).G)/(G-R_(A)) = (21 xx 500)/(500-21) = 10500/479 = 21.92 Omega`
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