Draw a schematic diagram of circuit consisting of a battery of 3 cells of 2V each, combination of three resistors `10 ohm`, `20 ohm` and `30ohm` connected in parallel, a plug key and an ammeter,all connected in series. Use this circuit to find the following
(i) Current through each resistor.
(ii) Total current in circuit
(iii)Total Effective resistance of circuit

Explanation

Data: `G=396 Omega, S=4 Omega`
`I_(g) = S/(S+G). I`
`therefore I_(g)/I= S/(S+G) = 4/(4+396) = 4/400 = 0.01`
This gives the fraction of the current through the galvanometer.
The fraction of the current through the shunt
`I_(s)/I=1-I_(g)/I=1-0.01 = 0.99`